15x^2-22+8=(5x-4)(3x-2)

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Solution for 15x^2-22+8=(5x-4)(3x-2) equation: 



15x^2-22+8=(5x-4)(3x-2)

We move all terms to the left:

15x^2-22+8-((5x-4)(3x-2))=0

We add all the numbers together, and all the variables

15x^2-((5x-4)(3x-2))-14=0

We multiply parentheses ..

15x^2-((+15x^2-10x-12x+8))-14=0



We calculate terms in parentheses: -((+15x^2-10x-12x+8)), so:

(+15x^2-10x-12x+8)

We get rid of parentheses

15x^2-10x-12x+8

We add all the numbers together, and all the variables

15x^2-22x+8

Back to the equation:

-(15x^2-22x+8)



We get rid of parentheses

15x^2-15x^2+22x-8-14=0

We add all the numbers together, and all the variables

22x-22=0

We move all terms containing x to the left, all other terms to the right

22x=22

x=22/22

x=1

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